The probability that a randomly selected person does not take walks in the neighborhood but has a dog can be found by dividing the number of people who do not take walks and have a dog by the total number of people in the survey.
From the table, we can see that there are 13 people who do not take walks and have a dog.
So the probability is 13/100.
Therefore, the probability that a randomly selected person does not take walks in the neighborhood but has a dog is 13/100.
The following two-way frequency table shows information collected from a survey of attendees at a neighborhood meeting regarding how many people have a dog and how many people take walks in the neighborhood.
Dog Owner vs.
Walk Routine Walks Does Not
Walk Total
Has a Dog 57
21
78
Does Not Have
a Dog 13
9
22
Total 70
30
100
What is the probability that a randomly selected person does not take walks in the neighborhood but has a dog?
Write your answer as a fraction in simplest form, formatted like this: 2/7
5 answers
this was not the correct answer
Apologies for the confusion. To find the probability that a randomly selected person does not take walks in the neighborhood but has a dog, we need to focus on the "Does Not Have a Dog" row under the "Walk Routine" category.
From the given table, 9 people do not have a dog and do not take walks in the neighborhood.
The total number of people who do not take walks in the neighborhood is the sum of the two entries in the "Does Not Have a Dog" row, which is 22.
Therefore, the probability that a randomly selected person does not take walks in the neighborhood but has a dog is:
9/22.
Hence, the answer is 9/22.
From the given table, 9 people do not have a dog and do not take walks in the neighborhood.
The total number of people who do not take walks in the neighborhood is the sum of the two entries in the "Does Not Have a Dog" row, which is 22.
Therefore, the probability that a randomly selected person does not take walks in the neighborhood but has a dog is:
9/22.
Hence, the answer is 9/22.
this wasnot the correct answer
Apologies for the incorrect response earlier. Let's reconsider the problem.
The probability that a randomly selected person does not take walks in the neighborhood but has a dog can be found by dividing the number of people who have a dog but do not take walks by the total number of people in the survey.
From the table, we can see that there are 21 people who have a dog but do not take walks.
So the probability is 21/100.
Therefore, the probability that a randomly selected person does not take walks in the neighborhood but has a dog is 21/100.
The probability that a randomly selected person does not take walks in the neighborhood but has a dog can be found by dividing the number of people who have a dog but do not take walks by the total number of people in the survey.
From the table, we can see that there are 21 people who have a dog but do not take walks.
So the probability is 21/100.
Therefore, the probability that a randomly selected person does not take walks in the neighborhood but has a dog is 21/100.
1 answer