Using the trapezoidal rule, we can estimate the integral as:
∫^50_0f(t)dt ≈ (10/2)(6.8 + 9.2) + (10/2)(9.2 + 13.4) + (10/2)(13.4 + 18.1) + (10/2)(18.1 + 20.8) + (10/2)(20.8 + 19.2)
Simplifying and computing, we get:
∫^50_0f(t)dt ≈ 940 million metric tons
Therefore, an estimate for the integral is 940 million metric tons.
The following table gives the approximate amount of emissions, E, of nitrogen oxides in millions of metric tons per year in the US. Let t be the number of years since 1940 and E=f(t).
1940 1950 1960 1970 1980 1990
t 0 10 20 30 40 50
E 6.8 9.2 13.4 18.1 20.8 19.2
Estimate the integral: ∫^50_0f(t)dt≈
1 answer