To model the population data provided, we start by acquiring a linear function in the form of \( f(x) = mx + b \), where \( x \) is the number of years after 2000.
Part 1: Find the Linear Function
We have the following population data points as (year after 2000, population):
- (0, 283.6)
- (10, 308.4)
- (20, 334.8)
- (30, 352.6)
- (40, 382.3)
- (50, 410.3)
- (60, 438.8)
- (70, 467.8)
- (80, 506.5)
- (90, 541.1)
- (100, 575.2)
To calculate the slope \( m \), we can use two points, for example, (0, 283.6) and (100, 575.2):
\[ m = \frac{f(100) - f(0)}{100 - 0} = \frac{575.2 - 283.6}{100} = \frac{291.6}{100} = 2.916 \]
Next, we use one of the points to find \( b \):
Using point (0, 283.6):
\[ f(0) = 2.916(0) + b \implies b = 283.6 \]
Therefore, the linear function modeling the population is:
\[ f(x) = 2.916x + 283.6 \]
Part 2: Find \( f(70) \)
To find \( f(70) \):
\[ f(70) = 2.916(70) + 283.6 = 204.12 + 283.6 = 487.72 \]
Rounding to one decimal place gives:
\[ f(70) = 487.7 \]
Part 3: State What \( f(70) \) Means
The value of \( f(70) = 487.7 \) means:
B. The projected population is 487.7 million in the year 2070.
Part 4: Predict the Population in 2080
To find the predicted population for 2080, we calculate \( f(80) \):
\[ f(80) = 2.916(80) + 283.6 = 233.28 + 283.6 = 516.88 \]
Rounding to one decimal place gives:
\[ f(80) = 516.9 \]
Part 5: Compare With Table Value for 2080
The value from the table for the year 2080 is 506.5 million. Our model prediction is 516.9 million.
The comparison shows:
A. This value is fairly close to the table value.
Summary of Answers:
- \( f(x) = 2.916x + 283.6 \)
- \( f(70) = 487.7 \) million
- It means B. The projected population is 487.7 million in the year 2070.
- The population in the year 2080 will be 516.9 million.
- This value is A. This value is fairly close to the table value.