The following table displays four solutions created through the dissolution of salt in water.

Solution: A. Mass of NaCl: 5.0 Volume of water: 50.0
Solution: B. Mass of NaCl: 5.0 Volume of water: 75.0
Solution: C. Mass of NaCl: 5.0 Volume of water: 100.0
Solution: D. Mass of NaCl: 5.0 Volume of water: 125.0
Among the provided solutions, which one exhibits the greatest concentration of salt?

1 answer

To determine the concentration of salt (NaCl) in each solution, we can calculate the concentration using the formula:

\[ \text{Concentration (C)} = \frac{\text{mass of solute (g)}}{\text{volume of solvent (L)}} \]

First, let's convert the volume of water from milliliters (mL) to liters (L) for each solution:

  • Solution A:

    • Volume = 50.0 mL = 0.050 L
    • Concentration = \( \frac{5.0 , \text{g}}{0.050 , \text{L}} = 100 , \text{g/L} \)
  • Solution B:

    • Volume = 75.0 mL = 0.075 L
    • Concentration = \( \frac{5.0 , \text{g}}{0.075 , \text{L}} = \frac{5.0}{0.075} \approx 66.67 , \text{g/L} \)
  • Solution C:

    • Volume = 100.0 mL = 0.100 L
    • Concentration = \( \frac{5.0 , \text{g}}{0.100 , \text{L}} = 50 , \text{g/L} \)
  • Solution D:

    • Volume = 125.0 mL = 0.125 L
    • Concentration = \( \frac{5.0 , \text{g}}{0.125 , \text{L}} = 40 , \text{g/L} \)

Now, summarizing the concentrations:

  • Solution A: 100 g/L
  • Solution B: 66.67 g/L
  • Solution C: 50 g/L
  • Solution D: 40 g/L

From these calculations, Solution A exhibits the greatest concentration of salt at 100 g/L.