the following sequence is geometric:

Question

4/3, 4/9, 4/27....
determine the general term, tn and the term t10

so the general term is:
(4/3)x (1/3) ^n

so the tenth term is:
4/177147

is this correct? thanks!

You have one too many factors of three in the denominator.
a = 4/3, r=1/3 so t₁₀=(4/3)*1/3⁹ = 4/3¹⁰