The following reation has the following standard thermodynamic parameters: delta H= -33.6 kJ/mol delta S= -59.8 J/(mol*K). C(g) + D(g) --> E(g)

Question

Calculate the temperature at which the reaction becomes nonspontaneous.

Answer 1

dG = dH - TdS
Set dG = 0 and solve for T
T = dH/dS = -33.6/-0.0598 = ?