.5 = x*x/(.55-x)
solve for x, then .55-x
The following reaction has an equilibrium constant of 0.50 at a given temperature.
HCHO(g) CO(g) + H2(g)
If you have 0.55 moles of HCHO(g) in a 1.0L container initially, how many moles of HCHO will be present when the system reaches equilibrium?
1 answer