Part A
I agree with Martina's reasoning that since 62 is an even number, 2 must be one of the factors in a factor pair. To find the missing factor, we can divide 62 by 2:
\[ 62 \div 2 = 31 \]
Therefore, one factor pair for 62 is (2, 31). In this pair, 2 is a factor, and 31 is the other factor that, when multiplied by 2, gives 62:
\[ 2 \times 31 = 62 \]
Part B
I disagree with Lucas's statement that 15 is both a prime number and a composite number.
A prime number is defined as a number greater than 1 that has no positive divisors other than 1 and itself. In contrast, a composite number is a number greater than 1 that has more than two positive divisors.
Since 15 has divisors of 1, 3, 5, and 15, it can be divided evenly by numbers other than 1 and itself (specifically 3 and 5). Thus, 15 meets the definition of a composite number, but it does not qualify as a prime number because it has more than two distinct factors. Therefore, 15 is solely a composite number.