The following question has two parts. First, answer part A. Then, answer part B. Use the model to answer the questions. Part A Carter wants to use the model above to solve 273÷13 . Explain how he would find parts A, B, and C of the model. (2 points) Question 2 (1 point) Part B The final quotient for 273÷13 is______

Answer 1

To answer Part A regarding how Carter can use a model to solve \( 273 \div 13 \):

1. Part A: Carter can break down the division problem into more manageable parts by using the model of repeated subtraction or a place value approach.

   • Part A: He could identify Part A as the dividend \( 273 \) and Part B as the divisor \( 13 \). He would then begin the division process by estimating how many times \( 13 \) can go into \( 273 \) by checking multiples of \( 13 \).
   • To find Part C, Carter would calculate \( 13 \times 20 = 260 \) and see how many times \( 13 \) fits into \( 273 \) by continuing to subtract \( 260 \) from \( 273 \) to find the remainder. This process shows that \( 20 \) fits into \( 273 \), giving a partial quotient.
   • After finding the partial quotient, he would continue the process by checking how many more times \( 13 \) can fit into the leftover \( 13 \) (i.e., the remainder), which gives an additional quotient of \( 1 \).
   • Thus, the complete steps lead to a total quotient of \( 20 + 1 = 21 \).

2. Part B: The final quotient for \( 273 \div 13 \) is 21.