I guess ^3sqrt() means cube root. If not, please elucidate.
y = ∛(x-3)
y^3 = x-3
y^3 + 3 = x
so,
f-1(x) = x3 + 3
domain and range of f is all reals.
likewise, range and domain of f-1 is all reals.
the following function is one-to-one find its inverse. find domain and range of f and f^-1 show work
f(x)=^3sqrt(x-3)
1 answer