The following dataset is a list of the number of siblings for 10 children at a playground describe the spread of the dataset using the mean absolute deviation..number of siblings = 0, 0?1,1,1,1,1,2,3,5

Answer 1

To calculate the mean absolute deviation for the dataset of number of siblings for 10 children, we first need to find the mean of the data set:

Mean = (0 + 0 + 1 + 1 + 1 + 1 + 1 + 1 + 2 + 3 + 5) / 11
Mean = 16 / 11
Mean = 1.45 (rounded to two decimal places)

Next, we calculate the absolute deviation for each data point from the mean:

|0 - 1.45| = 1.45
|0 - 1.45| = 1.45
|1 - 1.45| = 0.45
|1 - 1.45| = 0.45
|1 - 1.45| = 0.45
|1 - 1.45| = 0.45
|1 - 1.45| = 0.45
|2 - 1.45| = 0.55
|3 - 1.45| = 1.55
|5 - 1.45| = 3.55

Now, we calculate the sum of these absolute deviations:

Sum of absolute deviations = 1.45 + 1.45 + 0.45 + 0.45 + 0.45 + 0.45 + 0.45 + 0.55 + 1.55 + 3.55
Sum of absolute deviations = 10.35

Finally, we find the mean absolute deviation by dividing the sum of absolute deviations by the number of data points (10 in this case):

Mean absolute deviation = 10.35 / 10
Mean absolute deviation = 1.035

Therefore, the mean absolute deviation for the dataset of number of siblings for 10 children is 1.035. This indicates that, on average, the data points are about 1.035 units away from the mean.