Let's first put the data sets in order:
Car company A: 28, 30, 30, 31, 35, 35, 35, 38
Car company B: 25, 27, 29, 33, 34, 34, 36
Calculating the median:
For Company A:
Median = (31 + 35) / 2 = 33
For Company B:
Median = 29
Since 33 > 29, we can conclude that the cars from Company A have a higher median highway fuel efficiency than Company B.
Therefore, the correct answer is A). The cars from Company A have higher MEDIAN highway fuel efficiency than Company B.
Calculating the mean:
For Company A:
Mean = (28 + 30 + 30 + 31 + 35 + 35 + 35 + 38) / 8 = 32.25
For Company B:
Mean = (25 + 27 + 29 + 33 + 34 + 34 + 36) / 7 = 30.4286
Since 32.25 > 30.4286, we can conclude that the cars from Company A have a higher mean highway fuel efficiency than Company B.
Therefore, the correct answer is B). The cars from Company A have higher MEAN highway fuel efficiency than Company B.
Calculating the mode:
For Company A:
There is no unique mode as multiple values (35) appear most frequently
For Company B:
Mode = 34
Since Company B has a unique mode while Company A does not, we can conclude that the cars from Company B have a higher mode of highway fuel efficiency than Company A.
Therefore, the correct answer is C). The cars from Company B have a higher MODE of highway fuel efficiency than Company A.
The following data set represents the highway fuel efficiency in miles per gallon (mpg) of randomly selected cars from two car companies
Car company A: 35,28,35,30,31,38,35,30
Car company B: 29, 33, 36, 27, 34, 34, 25,
*Remember to put each set of numbers in order from LEAST to GREATEST before starting the problem.
Answer Options:
A). The cars from Company A have higher MEDIAN highway fuel efficiency than Company B.
B). The cars from Company A have higher MEAN highway fuel efficiency than Company B.
C). The cars from Company B have a higher MODE of highway fuel efficiency than Company A.
D). The cars from both companies have the same mean, median, and mode for highway fuel efficiency.
1 answer