The following data refer to a single-acting hydraulic press:

Question

2
Area of plunger = 0,09 ml
Stroke of plunger = 0,13 m
Force applied to plunger = 300 N Area of ram = 0,45 m
4
Ignore any losses, and calculate:
(a) The volume of liquid displaced by the plunger in 6 strokes.

Answer 1

To calculate the volume of liquid displaced by the plunger in a single stroke, we can use the formula for the volume of a cylinder:

\[ \text{Volume} = \text{Area} \times \text{Stroke} \]

Given the data:

• Area of the plunger (\( A_p \)) = 0.09 m²
• Stroke of the plunger (\( S \)) = 0.13 m

Now, calculate the volume displaced in one stroke:

\[ \text{Volume displaced in one stroke} = A_p \times S = 0.09 , \text{m}^2 \times 0.13 , \text{m} \]

\[ = 0.0117 , \text{m}^3 \]

Now, to find the volume displaced in 6 strokes:

\[ \text{Volume displaced in 6 strokes} = 6 \times \text{Volume displaced in one stroke} \]

\[ = 6 \times 0.0117 , \text{m}^3 = 0.0702 , \text{m}^3 \]

So, the volume of liquid displaced by the plunger in 6 strokes is:

\[ \text{Volume displaced} = 0.0702 , \text{m}^3 \]