The flywheel of an engine has a moment of inertia of 24 kg*m^2.

Question

a) if the radius of the wheel is 0.6m, what force is required to accelerate the wheel from rest to an angular velocity of 300 rpm in 6 seconds?
b) how many turns does it make during this time?

Answer 1

(a) compute the angular acceleration required in rad.s^2. Call it alpha

Torque = (moment of inertia)* (alpha)
= force * radius

Solve for force

(b) avg. rpm * (1 min/60s)* 6s
= 15 revolutions