The floor of a rectangular hall is of lenght 9m and weight 4m . how many tiles of 2cm by cm can be used to cover the floor completely

Answer 1

First, we need to find the total area of the floor:

Area = length x width
Area = 9m x 4m
Area = 36 square meters

Next, we need to convert the units to centimeters to match the size of the tiles:

Area = 36m^2 x 100cm/1m x 100cm/1m
Area = 36,000 square centimeters

Now we can find the number of tiles needed by dividing the total area by the area of each tile:

Number of tiles = Area of floor / Area of each tile
Number of tiles = 36,000 cm^2 / (2cm x 2cm)
Number of tiles = 9,000 tiles

Therefore, we would need 9,000 tiles of 2cm by 2cm to cover the floor completely.