You don't have enough information posted to work the problem; I assume the picture to which you refer gives the volume of NaOH.
mols NaOH = M x L = ?
mols HCl = mols NaOH
M HCl = mols HCl/L HCl.
The flask shown here contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.270 M NaOH.
What volume of NaOH is needed to reach the end point of the titration?
What was the initial concentration of HCl?
3 answers
Vol NaoH titration Ml Naoh (1L/1000 mL) (.270 M (NAOH)= mol NaOH
Then mol of NaOH mol HCL/.010L