The first step of the synthesis is described by the reaction below. When 1.000 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4, the theoretical yield of FeC2O42H2O is

Question

grams.

Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)

Answer 1

Since both reactants are given you know that this is a limiting reagent problem. Convert both reactants to moles.
moles Fe(NH4)2(SO4)2.6H2O = 1g/molar mass=??.
moles H2C2O4 = L x M = ??
These molecules reactant in a 1:1 ratio; therefore, the smaller number of moles is the limiting reagent and that is the Fe(NH4)2(SO4).6H2O.
Convert moles Fe(NH4)2(SO4).6H2O to moles of the product using the coefficients in the balanced equation.
Now convert moles product to grams product by moles x molar mass. This is the theoretical yield.