First Stage = x + 28, second = x
x + 28 + x = 152
Solve for x, then x + 28.
The first stage of a rocket burns 28 s longer than the second stage. If the total burn time for both stages is 152 s, how long does each stage burn? Describe how you found your answer.
I was originally thinking to divide 152 by 2 then add 28, but I realized that wouldn't work and now I'm lost. Any help is appreciated, thank you!
2 answers
time of burn of 2nd stage = x seconds
time of burn of 1st stage = x+28
x + x+28=152
2x = 124
x = 62
2nd stage takes 62 seconds
1st stage is x+28 = 62+28 = 96 sec
time of burn of 1st stage = x+28
x + x+28=152
2x = 124
x = 62
2nd stage takes 62 seconds
1st stage is x+28 = 62+28 = 96 sec