The figure is formed from rectangles. Find the total area. The diagram is not to scale.
An abnormally shaped polygon with 6 sides is shown.
An abnormally shaped polygon with 6 sides is shown. The polygon has a shape similar to a rectangle, but with the top right corner cut out. Starting on the far left side of the shape, there is a vertical side labeled 5 feet. Moving counterclockwise around the shape, there is a horizontal side along the bottom labeled 8 feet. There is a vertical side on the right side of the image labeled 3 feet. There is a horizontal side that cuts back into the shape labeled 3 feet. There is a vertical side extending up with no label. The final side is horizontal and connects this vertical side with the first vertical side that was labeled 5 feet. This side, which is at the top of the shape, has no label.
(1 point)
Responses
40 ft2
40 ft 2
34 ft2
1 answer
First, let's consider the large rectangle, which would exist if the top right corner wasn't cut out:
- Width = 8 feet (given)
- Height = 5 feet (given)
The area of this large rectangle would be: \( 8 \text{ ft} \times 5 \text{ ft} = 40 \text{ ft}^2 \)
Now, let's consider the area of the cut-out rectangle at the top right:
- Width = 3 feet (given)
- Height = 5 - 3 = 2 feet (the difference between the total height and the labeled vertical side)
The area of the cut-out rectangle would be: \( 3 \text{ ft} \times 2 \text{ ft} = 6 \text{ ft}^2 \)
To find the area of the polygon, we subtract the area of the cut-out rectangle from the area of the larger rectangle:
Total area = Area of large rectangle - Area of cut-out rectangle
Total area = \( 40 \text{ ft}^2 - 6 \text{ ft}^2 = 34 \text{ ft}^2 \)
Therefore, the total area of the polygon is \( 34 \text{ ft}^2 \).