The figure below shows three charges at the corners of an isoscleles triangle. The plus 3 mu C and negative 3 mu C charges form a dipole. Calculate the force negative 8 mu C charge exerts on the dipole.

Question

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Answer 1

To calculate the force that the -8 μC charge exerts on the dipole, we can use Coulomb's Law. Coulomb's Law states that the force between two charges is given by the equation:

F = (k * |q1 * q2|) / r^2

where F is the force between the charges, k is the electrostatic constant (9 × 10^9 N·m^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.

In this problem, the dipole consists of a +3 μC charge (q1) and a -3 μC charge (q2), and the -8 μC charge (q3) is acting on the dipole. We need to calculate the force that q3 exerts on the dipole.

First, we need to calculate the force exerted by q3 on each individual charge of the dipole. Let's calculate the force between q3 and the +3 μC charge (q1):

F1 = (k * |q1 * q3|) / r^2

where F1 is the force exerted by q3 on q1.

Next, let's calculate the force between q3 and the -3 μC charge (q2):

F2 = (k * |q2 * q3|) / r^2

where F2 is the force exerted by q3 on q2.

Since q1 and q2 are equal in magnitude, but opposite in sign, the total force on the dipole can be calculated by taking the difference between F1 and F2:

F_total = F1 - F2

Now we can substitute the given values into the equation.

Given:
q1 = +3 μC
q2 = -3 μC
q3 = -8 μC

First, let's calculate the forces between q3 and each charge of the dipole:

F1 = (k * |q3 * q1|) / r^2 = (9 × 10^9 N·m^2/C^2) * (|(-8 μC)*(+3 μC)|) / (r^2)

F2 = (k * |q3 * q2|) / r^2 = (9 × 10^9 N·m^2/C^2) * (|(-8 μC)*(-3 μC)|) / (r^2)

Next, calculate the total force on the dipole:

F_total = F1 - F2

Substitute the given values and calculate the forces:

F1 = (9 × 10^9 N·m^2/C^2) * (|(-8 μC)*(+3 μC)|) / (r^2)
F1 = (9 × 10^9 N·m^2/C^2) * (|(-24 μC^2)|) / (r^2)

F2 = (9 × 10^9 N·m^2/C^2) * (|(-8 μC)*(-3 μC)|) / (r^2)
F2 = (9 × 10^9 N·m^2/C^2) * (|(24 μC^2)|) / (r^2)

Finally, calculate the total force:

F_total = F1 - F2 = (9 × 10^9 N·m^2/C^2) * (|(-24 μC^2)|) / (r^2) - (9 × 10^9 N·m^2/C^2) * (|(24 μC^2)|) / (r^2)

Note: The distance between the charges (r) is not given, so we cannot calculate the exact value of the force without this information.

Answer 2

A point charge q equals plus 6 n Cis surrounded by an imaginary sphere of radius r equals 40 space c mcentered on the charge as shwon in figure below.

Answer 3

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To calculate the electric field at a point on the surface of the sphere, we can use the electric field formula for a point charge:

E = k * (q / r^2)

where E is the electric field, k is the electrostatic constant (9 × 10^9 N·m^2/C^2), q is the charge, and r is the distance from the charge.

In this case, the charge (q) is +6 nC and the radius (r) of the sphere is 40 cm.

First, let's convert the charge and radius to SI units:

q = +6 nC = +6 × 10^(-9) C
r = 40 cm = 0.4 m

Now we can substitute the given values into the formula to calculate the electric field:

E = k * (q / r^2)
E = (9 × 10^9 N·m^2/C^2) * (6 × 10^(-9) C) / (0.4 m)^2

Simplifying the equation:

E = (9 × 10^9 N·m^2/C^2) * (6 × 10^(-9) C) / (0.16 m^2)
E = (54 × 10^(-9) N·m^2/C) / (0.16 m^2)

E = 337.5 × 10^(-9) N/C

Finally, we can express the electric field in scientific notation:

E = 3.375 × 10^(-7) N/C

Therefore, the electric field at a point on the surface of the sphere is 3.375 × 10^(-7) N/C.