<---replaces #3--->The figure below is a net for a triangular prism. Side a = 22 feet, side b = 12 feet, side c = 16 feet, side d = 16 feet, and side e = 20 feet. What is the surface area of this figure?

Answer 1

We can start by breaking the net into its individual faces.

There are 3 rectangular faces:

- One face has dimensions 22 feet by 12 feet
- Another face has dimensions 16 feet by 12 feet
- The third face has dimensions 22 feet by 16 feet

There are 2 triangular faces:

- One face has base 16 feet and height 20 feet
- The other face has base 22 feet and height 20 feet

To find the surface area, we need to add up the areas of all five faces.

The area of each rectangular face is (length x width).

- First face: 22 ft x 12 ft = 264 sq ft
- Second face: 16 ft x 12 ft = 192 sq ft
- Third face: 22 ft x 16 ft = 352 sq ft

The area of each triangular face is (1/2 x base x height).

- First triangular face: (1/2) x 16 ft x 20 ft = 160 sq ft
- Second triangular face: (1/2) x 22 ft x 20 ft = 220 sq ft

Now we add up the areas:

264 + 192 + 352 + 160 + 220 = 1188 sq ft

Therefore, the surface area of this triangular prism is 1188 square feet.