The fifth term of an A.p. Exceeds the second term by 1.The tenth term exceeds twice the fourth term by 3

Question

* find first term and common difference
* sum of first twenty-five terms.

Answer 1

cd = 1 / (5 - 2) = 1/3

t = f + 6 cd

t = 2f + 3 = f + 2
... 4th = -1
... 1st = -1 - (3 * 1/3) = -2
... 25th = -2 + (24 / 3) = 6

s = (-2 + 6) * (25/2)