(i) Distance RT
Let RT = x
Using the cosine rule,
x² = 20² + 7² - 2(20)(7)cos30°
x² = 400 + 49 - 280cos30°
x² = 449 - 140
x = √309
RT = 17.6m
(ii) Distance of the foot of the taller pole from P
Let TP = y
Using the cosine rule,
y² = 20² + 3² - 2(20)(3)cos30°
y² = 400 + 9 - 120cos30°
y² = 409 - 72
y = √337
TP = 18.3m
(iii) Angle of elevation of T from P
Let ∠TPT = θ
Using the sine rule,
sinθ = (7/18.3)sin30°
sinθ = 0.38
θ = 22.3°
The feet of two vertical poles of heights 3metres and 7metres are in line with a point P on the ground, the smaller pole being between the taller pole and P at a distance 20metres from P. The angle of elevation of the top (T) of the taller pole from the top (R) of the smaller pole is 30◦. Calculate the: (i) distance RT (ii) distance of the foot of the taller pole from P, correct to 3s.fs. (iii) angle of elevation of T from P, correct to 1d.p. Please with full solution
2 answers
impatient much?
Once is enough, thank you.
Repeated postings will not get faster or better responses.
and the bot is still getting it wrong
Once is enough, thank you.
Repeated postings will not get faster or better responses.
and the bot is still getting it wrong