The theoretical probability of getting three heads when tossing three coins simultaneously can be calculated as the probability of getting heads on one coin (1/2) multiplied by itself three times, since the outcomes are independent events.
The theoretical probability = (1/2) * (1/2) * (1/2) = 1/8
The experimental probability of getting three heads can be calculated by the number of times three heads were observed (40) divided by the total number of times the experiment was conducted (100).
The experimental probability = 40/100 = 2/5
To find the difference between the experimental and theoretical probabilities, we can subtract them:
2/5 - 1/8 = 16/40 - 5/40 = 11/40
Therefore, the difference between the experimental probability of getting three heads and its theoretical probability is 11/40.
The experiment involved tossing three coins simultaneously. The experiment was carried out 100 times, and it was noted that three heads occurred 40 times. What is the difference between the experimental probability of getting three heads and its theoretical probability? Write the answer in the simplest form of fraction. :)
3 answers
is this the simplest form?
Apologies for the oversight. Let's simplify the answer further.
11/40 cannot be simplified because there is no common factor other than 1 between 11 and 40.
Therefore, the simplest form of the difference between the experimental probability of getting three heads and its theoretical probability is 11/40.
11/40 cannot be simplified because there is no common factor other than 1 between 11 and 40.
Therefore, the simplest form of the difference between the experimental probability of getting three heads and its theoretical probability is 11/40.
1 answer