the euation that best models the linearized data for a particular data set is log y=075821x+0.03442. find the approximate value of y when x=4. round your answer to the nearest whole number.

Answer 1

We know that the equation for the linearized data is log y = 0.75821x + 0.03442.
We want to find the value of y when x = 4.
So we substitute x=4 in the equation to get:

log y = 0.75821(4) + 0.03442
log y = 3.03284 + 0.03442
log y = 3.06726

To find y, we can exponentiate both sides of the equation:

y = 10^(3.06726)

y = 1219.269

Rounding to the nearest whole number, we get:

y ≈ 1219

Therefore, when x = 4, the approximate value of y is 1219.