dGrxn = dGo + RTlnQ
dGo = -RTlnKa
dGo = about +18.5 kJ
RTlnQ = about -31.5 kJ
dGrxn = about -13 kJ/mol
The equlibrium contstant for equation
HNO2(aq) + H2O(l) <--> H3O+ (aq) + NO2-(aq)
is Ka = 5.6 E-4 M at 25.0 C. What is the value of Delta G rxn at 25.0 C when [H3O+] = [NO2-] = 1.5E-3 M and [HNO2] = 0.75 M?
a) -13.0 kJ*mol-1
b) -16. 9 kJ*mol-1
c) -18.9 kJ*mol-1
d) -31.5 kJ*mol-1
The correct answer is A but I keep getting C as the answer. Can you please explain in details?
1 answer