To determine the decreasing order of the ability to form products, we can look at the magnitude of the equilibrium constant (Keq) for each reaction. The larger the Keq, the greater the amount of products formed.
From largest to smallest Keq:
1) 2, 3, 4, 1
Therefore, the correct arrangement is c) 2, 1, 3, 4.
The equilibrium constant has been determined in several reactions as follows:
1. N2(g) + O2(g) ⇔ 2NO(g) Keq = 4.8 x 10^–31
2. H2(g) + Cl2(g) ⇔ 2HCl (g) Keq = 4.0 x 10^31
3. 2CO(g) + O2(g) ⇔ 2CO2(g) Keq = 2.3 x 10^22
4. Cu(s) + 2Ag+(aq) ⇔ Cu2+(aq) + 2Ag(s) Keq = 2.0 x 10^15
The correct arrangement of the above reactions, in decreasing order of their ability to form products, is ________, ________, ________, and ________.
a) 1, 2, 4, 3
b) 1, 4, 3, 2
c) 2, 1, 3, 4
d) 2, 3, 4, 1
e) 3, 4, 2, 1
3 answers
are you sure?
Apologies for the confusion. Let's analyze the given equilibrium constants again:
1) N2(g) + O2(g) ⇔ 2NO(g) Keq = 4.8 x 10^–31
2) H2(g) + Cl2(g) ⇔ 2HCl(g) Keq = 4.0 x 10^31
3) 2CO(g) + O2(g) ⇔ 2CO2(g) Keq = 2.3 x 10^22
4) Cu(s) + 2Ag+(aq) ⇔ Cu2+(aq) + 2Ag(s) Keq = 2.0 x 10^15
Now, let's arrange them in decreasing order of their ability to form products:
1) 2, 1, 3, 4
Therefore, the correct arrangement is c) 2, 1, 3, 4.
1) N2(g) + O2(g) ⇔ 2NO(g) Keq = 4.8 x 10^–31
2) H2(g) + Cl2(g) ⇔ 2HCl(g) Keq = 4.0 x 10^31
3) 2CO(g) + O2(g) ⇔ 2CO2(g) Keq = 2.3 x 10^22
4) Cu(s) + 2Ag+(aq) ⇔ Cu2+(aq) + 2Ag(s) Keq = 2.0 x 10^15
Now, let's arrange them in decreasing order of their ability to form products:
1) 2, 1, 3, 4
Therefore, the correct arrangement is c) 2, 1, 3, 4.