x^2 + y^2 − 2x + 2y − 1 = 0 , notice how we indicate exponents
complete the square
x^2 + y^2 − 2x + 2y = 1
x^2 - 2x + 1 + y^2 + 2y + 1 = 1+1+1
(x-1)^2 + (y+1)^2 = 3
The equation x2 + y2 − 2x + 2y − 1 = 0 is the general form of the equation of a circle. What is the standard form of the equation?
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