x^2 + 12x = 73
let's complete the square, the easiest way to solve this particular one
x^2 + 12x + 36 = 73+36
(x + 6)^2 = 109
x + 6 = ± √109
x = -6 ± √109
the positive one looks like
√109 - 6
so a = 1, b = -6
a+b = -5
The equation x^2+12x=73 has two solutions. The positive solution has the form (sqrta)-(b) for positive natural numbers a and b. What is a+b?
Thanks
1 answer