To find the volume of a circular cone using the equation \( V = \frac{1}{3} \pi r^2 h \), we need to plug in the values for the height (\( h \)) and the radius (\( r \)).
Given:
- Height \( h = 3 \) feet
- Radius \( r = 2 \) feet
Substituting these values into the volume formula:
\[ V = \frac{1}{3} \pi (2^2) (3) \]
Calculating \( 2^2 \):
\[ 2^2 = 4 \]
Now substituting back in:
\[ V = \frac{1}{3} \pi (4)(3) \]
Calculating \( 4 \times 3 \):
\[ 4 \times 3 = 12 \]
So the equation now looks like:
\[ V = \frac{1}{3} \pi (12) \]
Calculating \( \frac{12}{3} \):
\[ \frac{12}{3} = 4 \]
Thus, we have:
\[ V = 4\pi \]
Now, we can calculate \( 4\pi \) using the approximate value of \( \pi \approx 3.14 \):
\[ V \approx 4 \times 3.14 = 12.56 \]
Therefore, the volume of the 3-foot-high circular cone with a radius of 2 feet is approximately:
\[ \boxed{12.57} \text{ cubic feet} \] (when rounded to two decimal places).
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