if the roots are 1,2,3, then
(x-1)(x-2)(x-3) = 0
expand to get (b)
By the way, none of the answers as written are equations. the correct answer would be
x^3 - 6x^2 + 11x - 6 = 0
The equation that has the roots 1, 2, 3 is:
(a) x3 + 6x2 – 11x + 6
(b) x3 – 6x2 + 11x – 6 *
(c) x3 + 6x2 + 11x + 6
(d) x3 – 6x2 – 11x – 6
how ?
1 answer
1 answer