of with -0.12t + 4.67 = lna + tlnb
-0.12t + 4.67 - lna = tlnb
ln b = (-0.12t + 4.67 - lna)/t
b = e^ ( (-0.12t + 4.67 - lna)/t )
The equation of the line of best fit is lnM = -0.12t + 4.67. Given that M = ab^t, find the value of b.
I got as far as -0.12t + 4.67 = lna + tlnb but I don't know where to go from there.
4 answers
ln M = - 0.12 t + 4.67
M = e ^ ( - 0.12 t + 4.67 )
M = e ^ ( - 0.12 t ) * e ^ 4.67
M = [ e ^ ( - 0.12 ) ] ^ t * e ^ 4.67
M = 0.88692 ^ t * 106.69774
M = 106.69774 * 0.88692 ^ t
So:
M = a * b ^ t
a = 106.69774 , b = 0.88692
M = e ^ ( - 0.12 t + 4.67 )
M = e ^ ( - 0.12 t ) * e ^ 4.67
M = [ e ^ ( - 0.12 ) ] ^ t * e ^ 4.67
M = 0.88692 ^ t * 106.69774
M = 106.69774 * 0.88692 ^ t
So:
M = a * b ^ t
a = 106.69774 , b = 0.88692
Excellent! I like that.
Thanks to you both :)
1 answer