You can't solve "precisely" for the value of x unless you say what x is.
You have only said what x is NOT equal to. Is the word NOT there by mistake?
The equation of the function is:
f(x)=4-2(x-6)^1/3, for x not equal to 5
calculate precisely the value of f(x).
so I got this:
5=4-2(x-6)^1/3
1=-2(x-6)^1/3
(-1/2)=(x-6)^1/3
(-1/2)^3=(x-6)
-.125=x-6
now the next step is suposed to be this but I don't understand how they got it.
abs[x-5]=0.875
If you solve for x using my orginal simplification I got 5.875 but this istn' right.
4 answers
well it said that in the book but it wants you to solve for x IF the function is equal to 5.
<< it wants you to solve for x IF the function is equal to 5. >> That is not the question you wrote at first. That is why I was confused by your question.
If x=5, then
f(5)= 4 -2*(-1)^1/3
The cube root of -1 is -1, so
f(5) = 4+2 = 6
If x=5, then
f(5)= 4 -2*(-1)^1/3
The cube root of -1 is -1, so
f(5) = 4+2 = 6
I am suposed to solve for x if the FUNCTION is equal to 5.
1 answer