The equation of the curve is

Y=x^3+3/2x^2
Find the coordinates of the stationary point

1 answer

To find the coordinates of the stationary point, we need to find where the derivative of the curve is equal to 0.

First, let's find the derivative of the curve:
Y' = 3x^2 + 3x

Setting Y' to 0:
3x^2 + 3x = 0
3x(x + 1) = 0
x = 0 or x = -1

Now we need to find the corresponding y-values for these x-values:
When x = 0:
Y = (0)^3 + 3/2(0)^2
Y = 0

When x = -1:
Y = (-1)^3 + 3/2(-1)^2
Y = -1 + 3/2
Y = 1/2

Therefore, the coordinates of the stationary points are (0, 0) and (-1, 1/2).