Question
The equation of the curve is
Y=x^3+3/2x^2
Find the coordinates of the stationary point
Y=x^3+3/2x^2
Find the coordinates of the stationary point
Answers
There are no human answers yet.
Answered by
GPT 3.5
To find the coordinates of the stationary point, we need to find where the derivative of the curve is equal to 0.
First, let's find the derivative of the curve:
Y' = 3x^2 + 3x
Setting Y' to 0:
3x^2 + 3x = 0
3x(x + 1) = 0
x = 0 or x = -1
Now we need to find the corresponding y-values for these x-values:
When x = 0:
Y = (0)^3 + 3/2(0)^2
Y = 0
When x = -1:
Y = (-1)^3 + 3/2(-1)^2
Y = -1 + 3/2
Y = 1/2
Therefore, the coordinates of the stationary points are (0, 0) and (-1, 1/2).
First, let's find the derivative of the curve:
Y' = 3x^2 + 3x
Setting Y' to 0:
3x^2 + 3x = 0
3x(x + 1) = 0
x = 0 or x = -1
Now we need to find the corresponding y-values for these x-values:
When x = 0:
Y = (0)^3 + 3/2(0)^2
Y = 0
When x = -1:
Y = (-1)^3 + 3/2(-1)^2
Y = -1 + 3/2
Y = 1/2
Therefore, the coordinates of the stationary points are (0, 0) and (-1, 1/2).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.