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The equation of a straight line l1 is 3y+4x=12.Find the gradient of l1.

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To find the gradient of a straight line, we need to rearrange the equation into the form y = mx + c, where m is the gradient.

3y + 4x = 12

3y = -4x + 12

y = (-4/3)x + 4

The gradient of this line is -4/3.

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