Y = (x-5)^2 - 4. (5,-6).
Y = (5-5)^2 - 4 = -4.
When x = s, y = -4 instead of -5.
Therefore, the given point is not on the parabola.
The equation of a parabola is
y=(x-5)^2-4. Is the point (5,-6) on this parabola?
2 answers
Correction: When x = 5, y = -4 instead of -6.