B. -6
To find the y-intercept of a function, we plug in x=0 into the equation.
y = 2(0) - 6
y = -6
Therefore, the y-intercept of the function y = 2x - 6 would be -6.
The equation of a function is y=2x−6 . If this function were graphed, what would its y -intercept be?
A. 6
B. -6
C. 2
D. -3
5 answers
x 4, 6
y 38,58
Write the equation of the linear function that models the relationship shown in the table.
A. y = 10x + 2
B. y = 10x - 2
C. y = -10x + 78
D. y = x + 34
y 38,58
Write the equation of the linear function that models the relationship shown in the table.
A. y = 10x + 2
B. y = 10x - 2
C. y = -10x + 78
D. y = x + 34
To find the equation of a linear function, we first need to find the slope of the line using the two given points (4, 38) and (6, 58).
Slope (m) = (y2 - y1) / (x2 - x1)
m = (58 - 38) / (6 - 4)
m = 20 / 2
m = 10
Now that we have the slope, we can use the point-slope formula to find the equation of the linear function:
y - y1 = m(x - x1)
y - 38 = 10(x - 4)
y - 38 = 10x - 40
y = 10x - 2
Therefore, the equation of the linear function that models the relationship shown in the table is:
B. y = 10x - 2
Slope (m) = (y2 - y1) / (x2 - x1)
m = (58 - 38) / (6 - 4)
m = 20 / 2
m = 10
Now that we have the slope, we can use the point-slope formula to find the equation of the linear function:
y - y1 = m(x - x1)
y - 38 = 10(x - 4)
y - 38 = 10x - 40
y = 10x - 2
Therefore, the equation of the linear function that models the relationship shown in the table is:
B. y = 10x - 2
(-1, 4) (1,0)
Write the equation of the linear function shown on the graph.
A. y = 2x + 2
B. y = 2x - 2
C. y = -2x - 2
D. y = -2x + 2
Write the equation of the linear function shown on the graph.
A. y = 2x + 2
B. y = 2x - 2
C. y = -2x - 2
D. y = -2x + 2
To find the equation of the linear function passing through the points (-1, 4) and (1, 0), we first need to calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
m = (0 - 4) / (1 - (-1))
m = -4 / 2
m = -2
Now that we have the slope, we can substitute one of the points into the point-slope formula to find the equation of the line:
y - y1 = m(x - x1)
Using the point (-1, 4):
y - 4 = -2(x - (-1))
y - 4 = -2(x + 1)
y - 4 = -2x - 2
y = -2x + 2
Therefore, the equation of the linear function shown in the graph is:
D. y = -2x + 2
m = (y2 - y1) / (x2 - x1)
m = (0 - 4) / (1 - (-1))
m = -4 / 2
m = -2
Now that we have the slope, we can substitute one of the points into the point-slope formula to find the equation of the line:
y - y1 = m(x - x1)
Using the point (-1, 4):
y - 4 = -2(x - (-1))
y - 4 = -2(x + 1)
y - 4 = -2x - 2
y = -2x + 2
Therefore, the equation of the linear function shown in the graph is:
D. y = -2x + 2