y=x^2 (2x+3)
x intercepts: x=0, or x=-1.5
y intercepts (when x=0), y[=0
b. dy/dx=6x^2+6x=0 or x=0 so stationary point is 0,0, and at 1,0
c. d^2/dx^2=12x+6 , at x=0, it is positive, so it is a minimum
at x=-1, it is negative, so a max
The equation of a curve is y = 2x^3 + 3x^2
Find:
x-intercept of the curve
y-intercept of the curve
b) Determine the stationery point of the curve.
i) for each point in(b) above, determine whether it is a maximum or a minimum
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