the equation is f(x)=a(a-p)^2+q. Which statment is true?

A. a is less than zero because the graph opens upwards a q is zero because there are 2 x-intercepts
B. a is greater than zero because the graph opens upwards a q is zero because there are 2 x intercepts
C. the values a and q have opposite signs because there is 2 xintercepts
D. the values a and q have the same sign because there is 2 xintercepts.
I chose B, is that correct?

3 answers

no one said anything about which way the graph opens.
Actually, without looking at the graph, there is no way to answer the question.
But, if there are 2 roots, then for sure C is correct, because
if it opens up, then the vertex is below the x-axis
if it opens down, then the vertex is above the x-axis.
Ya. Also I'm going on a break so cya everyone ill be back in a few minutes to check on your answers ๐Ÿ˜†๐Ÿ˜Š๐Ÿ’–๐Ÿงก๐Ÿ’›๐Ÿ’š๐Ÿ’™๐Ÿ’œ (btw I'm just a kid I'm in 6th grade but I'm really smart I have all a's in my class almost all 100's so yeah :3)
I know nobody asked but I'm just saying C:
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