represents the relationship of the height, in meters, over time, in seconds, of an object dropped from the height of 100 meters. What is the height of the object 2.5 seconds after it was dropped?(1 point)
Responses
38.75 meters
38.75 meters
100 meters
100 meters
138.75 meters
138.75 meters
3.19 meters
1 answer
To find the height of the object 2.5 seconds after it was dropped, you can substitute \( t = 2.5 \) into the equation \( h(t) = -9.8t^2 + 100 \).
Calculating:
\[ h(2.5) = -9.8(2.5)^2 + 100 \] \[ h(2.5) = -9.8(6.25) + 100 \] \[ h(2.5) = -61.25 + 100 \] \[ h(2.5) = 38.75 \]
So, the height of the object 2.5 seconds after it was dropped is 38.75 meters.
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