well, how about using the numbers given, in the formula given?
d=200t+50t^2
the equation for the motion of an object with constant acceleration is d=vt+0.5at^2where d is the distance travelled in ft, v is the starting velocity in ft/s a is the acceleration in ft/s^2 and t is time in seconds
a race car begins with a velocity of 200ft/s and accelerates at 100ft/s
what is the expression for the distance travelled after one sec
1 answer