Yes, delta T is 0.69.
Then new freezing point is 79.4-0.69 = ?
If your prof watches significant figures be careful with the final answer.
The equation for lowering the freezing point of a solvent is given in your manual. Given that the freezing point for the pure solvent is 79.4 °C , the molality is 0.1 m , and the freezing point depression constant is 6.9 °C/m , determine the freezing temperature for the naphthalene solution.
Tf= 79.4 oC
m=0.1m
Kf= 6.9 oC
What is delta T?
delta T= 0.1m(6.9 oC)= 0.69 ?
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