Plug in the numbers and solve the equation.
𝐴 = 12.93 𝑀^−1 [𝐹𝑒^2+] + 0.0017
0.106 = 12.93(Fe^2+) + 0.0017
Solve for (Fe^2+) = ?
The equation for a normal calibration curve for the detection of
iron(II) is determined experimentally to be
𝐴 = 12.93 𝑀^−1 [𝐹𝑒^2+] + 0.0017
Analysis of a sample with unknown concentration gives an
absorbance reading of 0.106. What is the concentration of iron(II) in
the unknown?
1 answer
1 answer