x = =-b/2a
b = -16 so -b = 16
a = 4
x= 16/8 = 2
Find y by substituting
The equation f(x) = 4x^2 − 16x + 9 represents a parabola. What is the vertex of the parabola?
(2, −7)
(−2, 57)
(4, 9)
(−4, −137)
is it a pls helpme
2 answers
the vertex on the x axis is 1/2 the way between roots...
4x^2-16x + 9
x=(16+-sqrt(256-4*36))/8
= 2 +-sqrt(112) /8
so half way will be when x is
2, so the first answer is correct
4x^2-16x + 9
x=(16+-sqrt(256-4*36))/8
= 2 +-sqrt(112) /8
so half way will be when x is
2, so the first answer is correct