To find the x and y intercepts of the equation \( 7x + 5y = 100 \):
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Find the x-intercept (where \( y = 0 \)): \[ 7x + 5(0) = 100 \implies 7x = 100 \implies x = \frac{100}{7} \] Thus, the x-intercept is \( \left(\frac{100}{7}, 0\right) \).
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Find the y-intercept (where \( x = 0 \)): \[ 7(0) + 5y = 100 \implies 5y = 100 \implies y = \frac{100}{5} = 20 \] Thus, the y-intercept is \( (0, 20) \).
Therefore, the x-intercept is \( \left(\frac{100}{7}, 0\right) \) and the y-intercept is \( (0, 20) \).
The correct answer is: C. The line crosses the x axis at \( \left(\frac{100}{7}, 0\right) \) and crosses the y axis at \( (0, 20) \).