this is just a quadratic in 2^x, since 2^2x = (2^x)^2
So, it factors into
(2^x-3)(2^x-2) = 0
So, 2^x = 2 or 3
That means x = 1 or log2(3)
The equation
2^2x−5×2^x+6=0
has two solutions. The smaller is ? and the larger is ?.
1 answer