The enthalpy of vaporization of mercury is 59.1 kJ/mol. The normal boiling point of mercury is 357*C. What is the vapor pressure of mercury at 25*C?

Answer 1

ln(P2/P1)=deltaH/R (1/T2-1/t1)

you have T2, T1 (convert them to K)

YOu can look up R, deltaH is given, You are looking for P2, and P1 is 101.3kpa (vapor pressure at boiling)

Answer 2

2.7182