I suppose you are to use M and m as the same.
0.121g/100 gH2O = solubility.
mol N2O = 0.121/60 = approx o.002 and 0.002/0.1kg solvent = 0.02m
p = KcC
1 atm = Kc*0.02
Kc = 1 atm/0.02 = 50 atm/m
p = KcC
1.600 = Kc from above *C
Solve for C in molality and convert to g/100 if desired.
The enthalpy of solution of nitrous oxide (N2O) in water is -12 kJ/mol and its solubility at 20 oC and 1.00 atm is 0.121 g per 100. g of water. Calculate the molal solubility of nitrous oxide in water at 1.600 atm and 20 oC. Hint, first find Henry's law constant at 20 oC and 1.00 atm.
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