The enthalpy of neutralization for the reaction of a strong acid with a strong base is -56 kJ/mol of water produced. How much energy will be released when 185.0 mL of 0.400 M HCl is mixed with 152.5 mL of 0.500 M NaOH?

3 answers

0.1850*0.400 = ?moles HCl
0.1525*0.500 = x moles NaOH
I have 0.07625 moles NaOH and 0.07400 moles HCl; therefore, 0.07400 moles H2O should be formed.
56 kJ/mol x moles H2O formed = heat released.
-4.1 KJ
That's what I have.