dE = q + w
q is -2.05 kJ/mol C10H22
w you must obtain from volume on the left - volume on the right, then w = -p*delta V.
The enthalpy change for the reaction below at 25oC is -2,051 kJ (per mole of C10H22). What is the internal energy change for the reaction at 25oC?
10 CO(g) + 21 H2(g) --> C10H22(l) + 10 H2O(l)
Enter your answer in kJ (per mole of C10H22), rounded to the nearest kilojoule.
2 answers
How do you calculate the volume on the left and on the right?
3 answers